CAMBER AND DEFLECTIONS

Presstress

M_A = (1076.2 K)(16.99 in) = 18279 k-in

M_B = (1076.2 K)(31.57 in) = 33961 k-in

(1/2)(2.083)(18279) = (19037) (-56.61) = -1077717
(44.42)(18,279) = 811953 (-33.71) = -27370942
(1/2)(44.42)(33,961 -18,279) = 348297 ( -26.30) = -9160217
(5.95)(7071.8) = 390552 ( -5.75) = -2245671
Σ=1569839 ( 58.00) = 91050662

Σ= 51196157

At Release:

Δ_{r e l e a s e} = \frac{51196157}{E I} = \frac{51196157}{(4286) (545894)} = 3.149 i n

At Erection:

Δ_{e r e c t i o n} = 1.80 \times Δ_{r e l e a s e} = 1.80 \times 3.149 = 5.669 i n

At Final:

Δ_{f i n a l} = 2.20 Δ_{r e l e a s e} = 2.20 \times 3.149 = 6.927 i n

At Release:

Δ_{r e l e a s e} = \frac{- 5 w I^{4}}{384 E I} = \frac{- 5 \times 799.0 p l f \times \frac{1}{12} f t / i n (116.00 f t \times {(12 i n / f t)}^{4})}{384 \times 4286000 l b / {i n}^{2} \times 545894 {i n}^{4}} = - 1.391 i n

At Erection:

Δ_{e r e c t i o n} = 1.85 \times Δ_{r e l e a s e} = 1.85 \times (- 1.391) = - 2.573 i n

At Final:

Δ_{f i n a l} = 2.40 Δ_{r e l e a s e} = 2.40 \times (- 1.391) = - 3.338 i n

At Erection:

Δ_{e r e c t i o n} = \frac{- 5 (180 p l f) (\frac{1}{12}) {(116 \times 14)}^{4}}{384 \times 4696000 \times 545894} = - 0.276 i n

At Final:

Δ_{f i n a l} = Δ_{e r e c t i o n} \times 3.00 = 3.00 (- 0.276) = - 0.829 i n

At Erection:

Δ_{e r e c t i o n} = \frac{- 5 (1670.8 p l f - 799.0 p l f) (\frac{1}{12}) {((115.0 f t) (12.0 i n / f t)}^{4}}{384 \times 4696000 \times 545894} = - 1.338 i n

At Final:

Δ_{f i n a l} = Δ_{e r e c t i o n} \times 2.30 = 2.30 (- 1.338) = - 3.078 i n

At Erection:

Δ_{e r e c t i o n} = - 0.110 (f r o m C o n t i n u i t y A n a l y s i s)

At Final:

Δ_{f i n a l} = 3.00 \times Δ_{e r e c t i o n} = 3.00 \times (- 0.110) = - 0.330 i n